알고리즘 문제풀이
[백준/BOJ] 백준 16360번 : Go Latin
GeniusJo
2020. 11. 5. 22:47
16360번: Go Latin
Your program is to read from standard input. The input starts with a line containing an integer, n (1 ≤ n ≤ 20), where n is the number of English words. In the following n lines, each line contains an English word. Words use only lowercase alphabet let
www.acmicpc.net
표에 표시된 규칙으로 글자를 나타내고, 표에 표시되지 않은 경우일 때는 끝에 "us"를 붙인다.
코드
#include <iostream>
#include <algorithm>
#include <string>
using namespace std;
int n;
string input;
string result;
int main()
{
cin.tie(NULL);
ios_base::sync_with_stdio(false);
cin >> n;
for (int i = 0; i < n; i++)
{
result = "";
cin >> input;
//표에 표시된 규칙으로 바꾼다
if (input.substr(input.size() - 1, 1) == "a")
{
result = input.substr(0, input.size() - 1);
result += "as";
}
else if (input.substr(input.size() - 1, 1) == "i")
{
result = input.substr(0, input.size() - 1);
result += "ios";
}
else if (input.substr(input.size() - 1, 1) == "y")
{
result = input.substr(0, input.size() - 1);
result += "ios";
}
else if (input.substr(input.size() - 1, 1) == "l")
{
result = input.substr(0, input.size() - 1);
result += "les";
}
else if (input.substr(input.size() - 1, 1) == "n")
{
result = input.substr(0, input.size() - 1);
result += "anes";
}
else if (input.substr(input.size() - 2, 2) == "ne")
{
result = input.substr(0, input.size() - 2);
result += "anes";
}
else if (input.substr(input.size() - 1, 1) == "o")
{
result = input.substr(0, input.size() - 1);
result += "os";
}
else if (input.substr(input.size() - 1, 1) == "r")
{
result = input.substr(0, input.size() - 1);
result += "res";
}
else if (input.substr(input.size() - 1, 1) == "t")
{
result = input.substr(0, input.size() - 1);
result += "tas";
}
else if (input.substr(input.size() - 1, 1) == "u")
{
result = input.substr(0, input.size() - 1);
result += "us";
}
else if (input.substr(input.size() - 1, 1) == "v")
{
result = input.substr(0, input.size() - 1);
result += "ves";
}
else if (input.substr(input.size() - 1, 1) == "w")
{
result = input.substr(0, input.size() - 1);
result += "was";
}
//표에 나타나지 않은 경우일때
else
{
result = input + "us";
}
cout << result << "\n";
}
return 0;
}